b | f | d* |
---|---|---|
\(0 \le b_{cur} \le b_{break}\) | Use (18) with x = 0 to find fcur | \(d_{b + 1}^{*} = d_{i}^{*} = \frac{{1 - f_{cur} }}{\alpha }\) |
\(b_{cur} > b_{break}\) | Use (19) with σ = σt and b = bcur to find x = xcur Use (18) with σ = σt, x = xcur and b = bcur to find fcur | \(d_{b + 1}^{*} = d_{i}^{*} = \frac{{1 - f_{cur} }}{\alpha }\) |